Question

evaluate the integral [1,2] (x^2-2/x)

Answer 1

x^3/3-ln[2]
8/3-ln[2]-2/3
so
2-ln[2]

Answer 2

integral of x^2 = x^3/3
integral of 2/x = 2ln(x)

Over the range [1,2] means value of (x^3/3 - 2ln(x)) @ 2 minus value @ 1.

Answer 3

GT is right...i messed up

Answer 4

i typed it wrong it's ((x/2)-(2/x))

Answer 5

Same concept. Integral of x/2 = x^2/4. Rest stands same.