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Mathematics 7 Online
OpenStudy (anonymous):

Can some one explain to me how to find the Relative Error and the percent of Error in simple terms please?

OpenStudy (anonymous):

let say i want to find the square root of 10 (which is not a perfect square.) so i might say that 10 is a little bit bigger than 9, so the sqrt of 10 is going to be a little bit bigger than 3, maybe 3.1. here 3.1 is an estimate. when an answer is estimated, error is created. and error is just the difference between the estimate and the actual if the estimate is lower than the actual, then the error will be a negative number. if the estimate is higher than the actual, then the error will be a positive number. relative error is just this difference divided by the actual value.

OpenStudy (anonymous):

and to find percent relative error, just multiply the relative error by 100 and write as a percentage.

OpenStudy (anonymous):

so lets say the when i did that i got 17.64705882 so the percent ill be 17%

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

yes, does the problem ask you to round to the nearest anything? if not, i would probably write it as 17.65%

OpenStudy (anonymous):

Nearest 10th wud be- 17.7? nearest 100th woud be 17.65

OpenStudy (anonymous):

you got it! good work.

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