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find the zeros by using the quadratic formula g(x)=2x^2+3x+1
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Given a function \(f\) of the form \(f(x)=ax^2+bx+c\), the quadratic formula tells us that the zeroes of \(f\) are given by the following expression.\[x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\ \longleftarrow \text{quadratic formula}\]If you still find yourself stuck, identify \(a\), \(b\),and \(c\) in your given function \(g\) by analogy to \(f\) that I stated above. Then, plug those values into the quadratic formula.
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