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2x-3y-4z=-21 -4x+2y-3z=-14 -3x-4y+2z=-10
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if you gone do it please show me how !
\[-3x+4y+2z = -10\]\[-4x+2y-3z = -14\]\[2x-3y-4z = -21\]
i need to find the value of x,y,z
Multiply the first equation by 2 and add it to the third equation. That will eliminate z
\[-6x+8y+4z = -20\] \[2x -3y-4z = -21\]
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ok
The result is -4x +5y = -41
Now multiply the top equation by 3 and the second equation by 2 and add. That will eliminate z again.
\[-9x+12y+6z = -30\]
\[-8x+4y-6z = -28\]
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When you add those two you get: \[-17x+16y = -58\]
So now you have two equations that contain only x and y. Do you know how to solve that system?
yes thanks
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