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help with quadratic formula 2x^2 - 7x - 30 = 0
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\[x=-b \pm \sqrt{b ^{2}-4ac}/2a\]
2x^2 - 7x-30 = 0 2x^2-12x+5x - 30 = 0 2x(x-6)+5(x-6) = 0 (x-6)(2x+5) = 0 x = 6,-5/2
let 2= a , b= 7, c= -30 just put into the formula
Hero is correct. Patissocoolike showed incorrect variables: let \[a=2 b=-7 c=-30\] the difference, of course, would be that b is -7 not 7
so does the -7 become 7 (-b)
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correct, since b is -7 when the equation calls for a -b the correct input will be +7
thx
Just factor it
No need for quad formulas if it's factorable
it is -7 but in the formula you automatically know you must use the opposite sign of b
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