Can Someone Help Me Solve : 2x^2-4x-6=0 ?

Question

lalaly · Answer

$$\large{2(x^2-2x-3)=0}$$$$\large{2(x-3)(x+1)}=0$$

anonymous · Answer

But My Teacher Doesn't Have That Answer On The Answer Sheet , So That's Why I'm Confused .

lalaly · Answer

did your teacher ask you to complete the square or factor?

anonymous · Answer

He Just Said Solve It .

lalaly · Answer

ok what are the answers u have?

anonymous · Answer

When I Asked In Class , Another Student Said : 3(2x+3)(2x-3) ?

lalaly · Answer

no thats wrong, try expanding the brackets
you get 12x^2-27 .. and thats not the same as ur equation

anonymous · Answer

That's What I Said . But The Only Other Choices I Have Too Pick From Is : 2(2x+1)(5x+2) And 5x^2+11x+3 .

anonymous · Answer

pick none of the above

lalaly · Answer

are you still tlking about the same question ? because u can solve it in two ways
the one i showed u above
or u can solve it by copleting the square
$$2(x^2-2x-3)=0$$$$2[(x-1)^2-1-3]=0$$$$2(x-1)^2-8=0$$$$(x-1)^2=\frac{8}{2}$$$$(x-1)^2=4$$$$x-1=\pm \sqrt4$$$$x=1+\sqrt4 = 1+2 =3$$and $$x=1-\sqrt4= 1-2= -1$$

anonymous · Answer

Oh Gosh , I'm SOOO Confused .

anonymous · Answer

that's just a different way of solving it

lalaly · Answer

if -1 and 3 are not one of ur choices then ur choices are wrong

anonymous · Answer

I Have Those Two ( -1 And 3 ) On My Paper , But He Don't Have Them Together . So I Thought I Was Doing It Wrong .