Mathematics
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OpenStudy (anonymous):
EMERGENCY: NEED HELP Thank You
Two blocks with masses m1 = 3.9 kg and m2 = 6.7 kg are connected by a string that hangs over a pulley of mass M = 2.2 kg and radius R = 0.11 m as shown above. The string does not slip. Assuming the system starts from rest, use energy principle find the speed of m2 after it has fallen by 0.4 m. Treat the pulley as a disk.
14 years ago
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OpenStudy (anonymous):
emergency?
14 years ago
OpenStudy (anonymous):
woops
14 years ago
OpenStudy (anonymous):
must of pated the whole thing
14 years ago
OpenStudy (anonymous):
pasted
14 years ago
OpenStudy (anonymous):
\[1/2 I^2 \omega=m gh\]
14 years ago
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OpenStudy (anonymous):
you know a diagram would really help
14 years ago
OpenStudy (anonymous):
|dw:1322958204517:dw|
14 years ago
OpenStudy (anonymous):
here's the diagram
14 years ago
OpenStudy (anonymous):
obviously, it will turn toward mass with bigger mass
14 years ago
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OpenStudy (anonymous):
net mass
6.7-3.9=2.8
2.8*9.8=27.44 newton
14 years ago
OpenStudy (anonymous):
\[1/2 I^2 \omega=m gh\]
\[1/2 I^2 \omega=27.44(.4)\]
you can find I and plug it in.
then solve for \[\omega\]
once you find \[\omega\], divide by r
14 years ago
OpenStudy (anonymous):
is mass for both or only the heavier one
14 years ago
OpenStudy (anonymous):
this
6.7-3.9=2.8
14 years ago
OpenStudy (anonymous):
ok I'll solve it add see if its right
14 years ago
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OpenStudy (anonymous):
yeah he incorporates integrals into the equations
14 years ago
OpenStudy (anonymous):
Is I= mr^2/2
14 years ago
OpenStudy (anonymous):
if so, is m for both masses?
14 years ago
OpenStudy (anonymous):
Is I= mr^2/2 yes
if so, is m for both masses?
net mass
14 years ago
OpenStudy (anonymous):
ok thank you, im gonna solve for the acce..
14 years ago
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OpenStudy (anonymous):
\[1/2 I^2 \omega=27.44(.4)\]
once you find I , plug it here and solve for omega
14 years ago
OpenStudy (anonymous):
I'm not quite getting realistic numbers
14 years ago
OpenStudy (anonymous):
I= 1/2 m r^2
= 1/2 (2.2)(.11)^2
I=0.01331
14 years ago
OpenStudy (anonymous):
i get 6097.77 for w
14 years ago
OpenStudy (anonymous):
wrong thing square
\[1/2 I \omega^2=27.44(.4)\]
\[1/2 (0.01331) \omega^2=27.44(.4)\]
w~~40.6114
14 years ago
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OpenStudy (anonymous):
oh tats why
14 years ago
OpenStudy (anonymous):
divide that by by radius
40.6114/.11m
14 years ago
OpenStudy (anonymous):
.11 meter that is
14 years ago
OpenStudy (anonymous):
369.19?
14 years ago
OpenStudy (anonymous):
that doesn't sound right
14 years ago
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OpenStudy (anonymous):
and if I multiply I get 4.467
14 years ago
OpenStudy (anonymous):
which is also the wrong answer for some reason
14 years ago
OpenStudy (anonymous):
is 63.63 right answer?
14 years ago
OpenStudy (anonymous):
I'll check
14 years ago
OpenStudy (anonymous):
Don't think its right
14 years ago
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OpenStudy (anonymous):
this question is frustrating
14 years ago
OpenStudy (anonymous):
hold on
14 years ago
OpenStudy (anonymous):
try 421.084
14 years ago
OpenStudy (anonymous):
did you try it?
14 years ago