Question

∫xe^x/(x+1)^2dx

Answer 1

i know its integration by parts

Answer 2

Hey. Let \[dv = 1/(x+1)^2\] and \[u=x*e^x\]

in that case, \[v = (-1/(x+1))\] and \[du = e^x(x+1)\]

Try to use integration by parts now, it should be easier now that I've given you the parts.

Let me know if you get the final answer.

Answer 3

http://www.wolframalpha.com/input/?i=integrate+x+e%5Ex%2F%28x+%2B+1%29%5E2