Question

1) For the quadratic equation, x^2 - 4x + c = 0 where the equation has only one solution... Find the value of c.

Answer 1

If there is only one solution, then the discriminant, b^2 - 4ac must be 0. So (-4)(-4)-4(1)(c) = 0

16-4c = 0 c = 4

Answer 2

This is completeing the square right? So you would divide -4 by 2, then square it, so you'd get -2 squared = 4