Question

integral (x^2 -x+2)/(x^3 -1) dx

Answer 1

this a job for partial fractions
ick

Answer 2

yh

Answer 3

somehow i am getting a positive with tan^-1 in the answer

Answer 4

something like
\[\frac{x^2-x+2}{x^3-1}=\frac{a}{x-1}+\frac{bx+c}{x^2+x+1}\] and then integrate that thing

Answer 5

yeah i think
\[\frac{bx+c}{x^2+x+1}\] will give an inverse tangent.

Answer 6

yh i got inverse tan but with a positive(according to the book it is negative)