Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

1^infinity=?

OpenStudy (anonymous):

1

OpenStudy (anonymous):

indeterminate

OpenStudy (anonymous):

undetermined form how?

OpenStudy (anonymous):

how can we not evaluate it

OpenStudy (anonymous):

Infinity is not a real number. There are no rules for how exponentiation works on something that isn't a number

OpenStudy (anonymous):

cant evaluate because infinity is not a real number

OpenStudy (anonymous):

but 1^infinity means 1 is multiplied by it self infinity times in this way ans is 1 isn't it?

OpenStudy (anonymous):

it could be reducible to 1

OpenStudy (anonymous):

1^infinity=0

OpenStudy (anonymous):

any number^infinity=0

OpenStudy (anonymous):

@ Milad.p. you are wrong 1^infinity is not 0 it is undetermined. check from Wikipedia side. and give answer to anyone only when you know the right ans. don't give wrong ans.

OpenStudy (anonymous):

\[f(x) = x^{\infty} = \left\{\begin{array}{r} 1, &x=1 \\0, &0\le x<1 \\ \infty, &x>1\end{array}\right.\] This is my first attempt at piecewise function :-D

OpenStudy (anonymous):

Im sorry But it's not my wrong this is my teacher's Wrong , again sorry Best Regard

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!