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can some one please please please help me solve this problem the file is attached in the answer box
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given g(x) is area under the curve f(t) between t=1 and t=x we know area under a curve is the integral of the curves betwwwn the limits so \[G(x)=\int\limits_{1}^{x} 1/t dt\]
now if we integrate to find G(x) G(x)= [ln t] with lower limit 1 and upper limit x G(x)=ln x now G(1)= ln 1 =0 G(1)=0
|dw:1323108973980:dw| G(x+h)-G(x) is the area marked in the graph
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