4t^2 - 36/49=0
please set by step and answer
the only time a fraction is 0 is when the top is 0 assuming that thats all spose to be a numberatot
numerator .... i passed typing class, honest lol
I think he means \(4t^2 - \frac{36}{49}=0\).
\[4t^2-36/49 = 0\]
add, sqrt, and simplify ... is what i see
ty
2t = 6/7 t = +- 3/7 if i see it right
how do you get 6/7
if you need any steps filled in, just say so :)
4t^2 - (36/49) = 0 add 36/49 to each side 4t^2 = 36/49 now take the square root of each side 2t = 6/7 and divide off that 2 t = 6/(7*2) and simplify t = 3/7 we need to address the +- in some cases
since t^2 is our original arguement; either a positive or a negative value works in it +- 3/7
okay thanks
yep, there are other ways, but that one seems pretty straight forward to me :)
i have many more questions? do you want me to keep asking here or start new question?
start new ones so that others can have a chance to help
k ty
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