Question

8(z-3)=2(z+12) Is this the right answer? z=3 and z=12

Answer 1

you can get only one answer

Answer 2

Ok what did something wrong?

Answer 3

You should start by distributing the brackets.
\[a(b-c)=a*b+a*(-c)\]

Answer 4

What would be the correct way to solve this?

Answer 5

?

Answer 6

expand the terms and collect them

Answer 7

If \[a(b-c)=a*b+a*(-c)\]then\[8(z-3)=?\]and\[2(z+12)=?\]

Answer 8

So will I multiply 8*z and 8*3

Answer 9

yep, and same thing to the other side

Answer 10

Bingo! But remember that the 3 is \(negative\), so the product of 8 and -3 will also be negative.

Answer 11

so What do I do to the answers on both sides?

Answer 12

So am I adding 8z and 2z together?