Question

If you toss two six-sided die, what is the probability of getting at least one 3?

Answer 1

11/36

Answer 2

5/6*1/6*2+1/6*1/6

Answer 3

what does that work out to? I can't really understand the way you typed it!

Answer 4

it works out to 11/36

Answer 5

\[\frac{5}{6}\cdot\frac{1}{6}\cdot2+\frac{1}{6}\cdot\frac{1}{6}\]

Answer 6

ah...
Thank you...
How does that work though?

Answer 7

you can get one three OR two three, so:
first possibility:
first throw: 3; probability 1/6
second throw: anything except 3; probability 5/6
total first probability 1/6*5/6

second possibility:
first throw: anything except 3; probability 5/6
second throw: 3; probability 1/6
total second probability 5/6*1/6

third possibility
first throw: 3; probability 1/6
second throw: 3; probability 1/6
total third probability 1/6*1/6


and now add everything

Answer 8

You get
1, 3
2, 3
...
6, 3

6 choices

3, 1
3, 2
3, 4
3, 5
3, 6

3,3 from this list is excluded because there's a same one from the previous list.
5 choices

6 + 5 = 11

Answer 9

but aren't you double counting? The order doesn't matter in this situation, right?

Answer 10

I didn't double count. no, the order matters
since there are two dices

Answer 11

it matters, because it's different

Answer 12

but wouldn't 1,3 be the same thing as 3, 1, because you toss the die at the same time?!?
I don't know the answer to this question, and I won't be told until January, so THANK YOU for helping me! :D

Answer 13

probability is equal but it's not the same

Answer 14

This is a basic probability question

Answer 15

you can try simple experiment with tossing coins and checking how many times you get at least 1 head, so 1head and 1 tail or 1 tail and 1 head or 1 head and 1 head

Answer 16

you will see that probability will be somewhere near answer

Answer 17

Thanks for that help...
Then this is a permutation, not a combination? If they are not the same, then order does matter?

Answer 18

with permutations and combination you don't calculate probabilities

Answer 19

I'd rather not say.

So to find the total number of solutions with 3s in them...I think I get your way(s), though my friend says that it's:
5 ways to get one 3, and 1 way to get two 3s.
this is 6 over:
(6*6)/2
which is 6/18, or 1/3.
I am slightly confuzzled.