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subtract. simplify, if possible. 4x-36 over x^2-81 minus 4x-36 over 81-x^2
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\[\frac{4x-36}{x^2-81}-\frac{4x-36}{81-x^2}=\frac{4x-36}{x^2-81}+\frac{4x-36}{x^2-81}\] \[=\frac{8x-72}{x^2+81}\]}
you have the correct setup, but not what they are looking for
another typo, it should be \[=\frac{8x-72}{x^2-81}\] now maybe we can factor and cancel
\[\frac{8(x-9)}{(x+9)(x-9)}=\frac{8}{x+9}\]
thank you :) *muah*
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