What is the magnitude of the angular momentum of a 5.0g particle moving counterclockwise (as viewed from above) with an angular speed of 4pi rads/s in a horizontal circle of radius 17cm ?

Question

What is the magnitude of the angular momentum of a 5.0g particle moving counterclockwise (as viewed from above) with an angular speed of 4pi rads/s  in a horizontal circle of radius 17cm ?

anonymous · Answer

I used the formula L= Iw but I got it wrong, can someone help me please...........................and also what will be the direction of the angular momentum?

anonymous · Answer

the direction is determind by the right hand law http://en.wikipedia.org/wiki/Right-hand_rule this gives that counter clokwise movment u name the direction of angular momentum facing to u from the page. The magnitude is given by L=Iw do u know how to calculate I? its I=m*r^2

anonymous · Answer

see also my answer to ruchi about moment of inertia! http://openstudy.com/?F1235843513972SWVWO2=_#/updates/4ee1c220e4b0a50f5c55fa40 good luck! :)

anonymous · Answer

Thankx