Question

Find the vertex of the quadratic function: -x^2-4x+5=0

Answer 1

I got (-2,9). I want to know if I'm correct.

Answer 2

we can complete the square to see

Answer 3

(-x^2-4x) + 5

-(x^2+4x+4)+5-4

-(x+2)^2 +1

looks to be -2,1 if i did it right

Answer 4

You don't need to complete the square, although that is one way of doing it. Just use x=-b/2a to find the x-coordinate of the vertex. Then plug that back into the equation to get the y-coordinate.

Answer 5

opps, need to add the 4 .....-2,9, lets chk the wolf

Answer 6

i got -2,7

Answer 7

-2,9 is good

Answer 8

a=the coefficient of x^2 and b=the coefficient of x. So, yes, your answer is (-2,9).

Answer 9

wow, thank you so much :)