Question

Simplify 7 log3 k + 6 log3 m – 9 log3 n? can someone show the steps on how you do this?

Answer 1

A. log3
B. 4 log3
C. log3
D. 4 log3 (k + m – n)

Answer 2

Let's first recall a couple of log identities:
\[\left[\begin{matrix}\text{First} & x*\log(y) = \log(y^x) \\ \text{Second }& \log(x*y) = \log(x) + \log(y) \\\text{Third} & \log({x \over y}) = \log(x) - \log(y) \end{matrix}\right]\]From the First identity:\[\log(k^7) + \log(m^6) - \log(n^9)\]From the Second and Third Identity\[\log({k^7 m^6 \over n^9})\]

Answer 3

hey eashmore, could you look at problem D on greenday's A 1100 kg car is traveling at 24 m/s. post?

Answer 4

that is choice C, but it has 3with the log?

Answer 5

Same difference. I omitted the base for ease of typing it up. Remember these identities only apply when the base is the same.

Answer 6

so are you master of the logarithms now?

Answer 7

not totally..lol

Answer 8

keep it up.. have fun

Answer 9

lol..do you know a good website to graph functions?

Answer 10

http://www.wolframalpha.com

Answer 11

What is the function? I'll type it in so you have an idea of how to type things in.

Answer 12

oh yeah...totally forgot about tht..thanks

Answer 13

thanks eashmore for the physics help

Answer 14

f(x) = log0.3 x

Answer 15

A base of 0.3?

Answer 16

http://www.wolframalpha.com/input/?i=plot+log_0.3%28x%29

Answer 17

yes