How can you make x the subject in this --> y=x^3-2x^2
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OpenStudy (amistre64):
declare a state of insolvency and elect a new parliment ... is just my first instinct
OpenStudy (mr.math):
LOL!
OpenStudy (mr.math):
New president?
jhonyy9 (jhonyy9):
y=x2(x-2)
- hope you will like it
OpenStudy (mr.math):
It's very difficult to solve for x.
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OpenStudy (amistre64):
can we make it a perfect cube?
OpenStudy (mr.math):
We can't!
OpenStudy (anonymous):
I knew there was something wrong!! But how can you then solve this question..if rate of change of y is 4 units per second, find rate of change at x at the given instant y=x^3-2x^2, x=3
OpenStudy (amistre64):
rate of chage is derivatives
OpenStudy (amistre64):
y' = 3x^2 -4x gives the rate of change at any given moment
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OpenStudy (mr.math):
So y and x are both functions in t?
OpenStudy (anonymous):
y'= 3 x^2 x' -4 x x'
OpenStudy (amistre64):
if x(t) = t; then x' = t' = 1
OpenStudy (mr.math):
If they are both functions of t, then do as Imran just did above, and solve it for x'.
OpenStudy (anonymous):
y'=4
x=3
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