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Mathematics 20 Online
OpenStudy (anonymous):

PLZ HELP ME :'( See attachment for Q

OpenStudy (anonymous):

OpenStudy (anonymous):

x = -3 and x = -1 (x+3)(x+1) = 0

OpenStudy (anonymous):

aka \[x^2+4x+3\]

OpenStudy (anonymous):

it said x^2+4x+3 is wrong

OpenStudy (anonymous):

eashmore was right: if the roots are -3 and -1, the equation has to be: \[(x+3)(x+1)\] Expantion:\[(x+3)(x+1)=x^2+3x+x+3=x^2+4x+3\] I don't see how it could be anything else.

OpenStudy (anonymous):

OpenStudy (anonymous):

its x^2-10x+25=0

OpenStudy (anonymous):

Not for the problem you first posted. Dryanni's answer is right for that where the solution for x is -3 and -1.

OpenStudy (anonymous):

For where x=5 is the solution, then x^2-10x+25=0 is correct.

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