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x^-4x+2=0 solve the quadratic equation by completing the square
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x^2-4x+2 = 0
?
You forgot to put the square after x
aww icic lol thank ya
x^2-4x = -2 x^2-4x + 4 = -2 +4 (x - 2)^2 = 2 x - 2 = +/- sqrt{2} x = +/- sqrt{2} + 2
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so then if i have i have to pick between the from (x+__)^2 or (x-__)^2 i would pick the minus
and apply the (x-2)^2=2?
(x-2)^2 The 2 is only negative because the middle term of x^2-4x +4 is negative
aww ok ok thank
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