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2^x +1/2^x-1 = 5
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hmmm i got till \[2^{x+1}=3\]
wait
2^x + 2^(1-x) = 5 2^x = a a + 2/a = 5 a^2 - 4a + 2 = 0 now you can do it on your own
x=3/2?
the answer is 0.585 ishaan94 i don't get how you got "2/a" and then what did you do from going to the second last step to the last step?
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is it \[2^{x}+1/2^{x}-1=5\] or \[2^{x+1}/2^{x-1}=5\]
Ishaan's got a good method, but I think he got his numbers a little bit wrong.\[2^x+\frac{1}{2^x}-1=5\]\[\Leftrightarrow a+\frac{1}{a}=6\]\[\Leftrightarrow a^2+1=6a\]\[\Leftrightarrow a^2-6a+1=0\]
\[\left(\frac{1}{2}\right)^{1-x}\] \[ 2^{-(1 -x)}\]
thanks
king it's the first one
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