You are to set up a code of 3-digit words using the digits 1,2,3,4,5,6 without using any digit more than once in the same word. a) What is the maximum number of words in such a language? b) If the words 124, 142, etc., designate the same word, how many different words are possible? plez help--and example part a and part b of the question separately so i dont get confused. thanx
"i ment explain part a and part b of the question separately so i dont get confused. thanx again
A) 120 B) 20
heyy strobe how did u do that problem?
A) is 6 P 3 B) is 6 C 3 So for A think of it this way. For the first letter in the word there are 6 numbers you can choose. Then for the second there are 5 as you've already used one. For the third there are 4 you can choose. 6 * 5 * 4 = 120 For B, there are 6 ways you can arrange 3 items, so since different rearrangements of the same 3 numbers are considered the same, the answer is 120 / 6 = 20
thanx for helping but i still dont understand it :( uhh i hate math ;(
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