Question

How do I solve an indefinite integral such as (x+4)/((x^2+8x-7)^2 ? I'm not sure how to handle the fraction...

Answer 1

Let u = x^2 + 8x - 7

du/dx = 2x + 8

dx = du/2x +8

integral ((x+4)/ u^2) * du/ (2x +8) -> integral ((x+4)/ u^2) * du/ 2(x+4)

= 1/2 integral 1/u^2

integrate it you will get -1/2u + C

Then sub u - x^2 + 8x - 7 back in.

Answer 2

u = x^2 + 8x - 7*