Mathematics
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OpenStudy (anonymous):
Simplify the following expression, and rewrite it in an equivalent form with positive exponents.
-30x^4y^-4/120x^-2y^-4
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OpenStudy (anonymous):
This is what I got for an answer let me know if I am right (-30/120) * (x^4y^-4/x^2y^-4)
-4y/x^2
OpenStudy (anonymous):
jhonyy is that right so far or is it wrong
jhonyy9 (jhonyy9):
is wrong
OpenStudy (anonymous):
okay
jhonyy9 (jhonyy9):
so -30/120 =
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OpenStudy (anonymous):
.4
jhonyy9 (jhonyy9):
in farction form
jhonyy9 (jhonyy9):
fraction
jhonyy9 (jhonyy9):
i like yoi learn it
jhonyy9 (jhonyy9):
you
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jhonyy9 (jhonyy9):
camon
OpenStudy (anonymous):
in fraction form is 2/5
jhonyy9 (jhonyy9):
why ?
OpenStudy (anonymous):
2 divides into 5 .4 times
jhonyy9 (jhonyy9):
-30/(4*30)
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OpenStudy (anonymous):
-225 is the answer for that
jhonyy9 (jhonyy9):
no than will be -1/4
OpenStudy (anonymous):
how?
jhonyy9 (jhonyy9):
so x4/x(-4) = x(4-(-4))
jhonyy9 (jhonyy9):
how ? because 120=4*30
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jhonyy9 (jhonyy9):
30 simplify by 30 and will remain -1/4
OpenStudy (anonymous):
okay
jhonyy9 (jhonyy9):
do you understand now sure ?
OpenStudy (anonymous):
yes
jhonyy9 (jhonyy9):
ok so there is x4/x(-2) than will be x on (4-(-2)) = x on 4+2 = x6
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jhonyy9 (jhonyy9):
yes ?
OpenStudy (anonymous):
yes
jhonyy9 (jhonyy9):
so y(-4)/y(-4) = ?
jhonyy9 (jhonyy9):
a/a = ?
jhonyy9 (jhonyy9):
camon
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jhonyy9 (jhonyy9):
easy
OpenStudy (anonymous):
y^16
jhonyy9 (jhonyy9):
no
OpenStudy (anonymous):
y^8
jhonyy9 (jhonyy9):
a/a = ?
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OpenStudy (anonymous):
a^2
jhonyy9 (jhonyy9):
a divide a
OpenStudy (anonymous):
=1
jhonyy9 (jhonyy9):
yes
OpenStudy (anonymous):
y^-4/y^-4 = y
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jhonyy9 (jhonyy9):
because y(-4)/y(-4) =1
because are the same terms
jhonyy9 (jhonyy9):
is 1
jhonyy9 (jhonyy9):
right
jhonyy9 (jhonyy9):
understandably now ?
OpenStudy (anonymous):
yes but what is my final answer gonna be 1/4x^6/y or turn it around?
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jhonyy9 (jhonyy9):
-x6/4
OpenStudy (anonymous):
okay so I am not gonna have the y in there right?
jhonyy9 (jhonyy9):
yes your answer without y
jhonyy9 (jhonyy9):
but with minus
OpenStudy (anonymous):
okay now I understand
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jhonyy9 (jhonyy9):
(-1/4)(x6) or (-x6)/4
jhonyy9 (jhonyy9):
understandably sure ?
OpenStudy (anonymous):
yep understanbly
jhonyy9 (jhonyy9):
do you have again ?
jhonyy9 (jhonyy9):
anything
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OpenStudy (anonymous):
nope I have a different question now to ask
OpenStudy (anonymous):
Simplify the following expression
\[\sqrt{-121} \sqrt{-24}\]
jhonyy9 (jhonyy9):
121=11*11
-1=i*i
24=6*4
jhonyy9 (jhonyy9):
minus * minus = ???
OpenStudy (anonymous):
okay thought that was right but wasn't sure if it had the "i" in it or not
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OpenStudy (anonymous):
positive
jhonyy9 (jhonyy9):
yes than result that in your answer not will exist i
OpenStudy (anonymous):
okay
jhonyy9 (jhonyy9):
than sqrt(-121*(-24))= ?
OpenStudy (anonymous):
one sec
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OpenStudy (anonymous):
53.9
jhonyy9 (jhonyy9):
why ? how you have got it ?
jhonyy9 (jhonyy9):
make the calcule here
OpenStudy (anonymous):
well sqrt -121 is 11 and sqrt of -24 is 4.89 rounded up will be 4.9 so times 11*4.9 and get 53.9
jhonyy9 (jhonyy9):
no
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OpenStudy (anonymous):
okay
jhonyy9 (jhonyy9):
there is sqrt(-121)*sqrt(-24)=sqrt(-121*(-24))=sqrt(121*24)=sqrt(11*11*4*6)
=11*2sqrt6=22sqrt6
OpenStudy (anonymous):
how do you get a sqrt of 6 ?
jhonyy9 (jhonyy9):
24=6*4
jhonyy9 (jhonyy9):
sqrt24=sqrt(6*2*2)=2sqrt6
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OpenStudy (anonymous):
sqrt of 6 is 2
jhonyy9 (jhonyy9):
no sqrt of 4 = sqrt 2*2 =2
OpenStudy (anonymous):
okay your right
jhonyy9 (jhonyy9):
now all is understandably ?
OpenStudy (anonymous):
yes
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jhonyy9 (jhonyy9):
have you again ?
OpenStudy (anonymous):
no that is the last problem
jhonyy9 (jhonyy9):
ok bye
jhonyy9 (jhonyy9):
Andrew from Hungary
OpenStudy (anonymous):
Aaron From US
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OpenStudy (anonymous):
And Thank you it was also nice meeting you
jhonyy9 (jhonyy9):
nice to meet you
jhonyy9 (jhonyy9):
good luck
OpenStudy (anonymous):
you too
jhonyy9 (jhonyy9):
bye
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OpenStudy (anonymous):
bye
OpenStudy (anonymous):
Start with the inner expression, -30x^4, and work outwards.
( ( ( (-30x^4 )y^-4 )/120 )x^-2 )y^-4 =\[-\frac{30 x^4}{\left(\left(y^4 120\right) x^2\right) y^4}= \]\[-\frac{x^2}{4 y^8} \]