Which of the following is not an equivalent form of the compound inequality x - 1 < -12 or x + 12 > 10 Answer x < -11 or x > -2 A number line with an open circle on -11, shading to the left, and an open circle on -2, shading to the right. x > -2 or x < -11 A number line with an open circle on -11, an open circle on -2, and shading in between.
x - 1 < -12 or x + 12 > 10 x < -12+1 or x > 10-12 x < -11 or x > -2 So choice A is out the question ------------------------------------------------------- This graphs to "A number line with an open circle on -11, shading to the left, and an open circle on -2, shading to the right.", so choice B is out ------------------------------------------------------- choice C is just a flip of choice A, so thats out too So the answer is choice D by process of elimination
Choose the correct description of the graph of the compound inequality x - 3 < -11 or x + 5 14 Answer A number line with a closed circle on -8, an open circle on 9, and shading in between. A number line with a closed circle on -8, shading to the left, and an open circle on 9, shading to the right. A number line with an open circle on -8, a closed circle on 9, and shading in between. A number line with an open circle on -8, shading to the left, and a closed circle on 9, shading to the right.
missing a sign...please give me a sign lol
> or <
mhm >=
k thx
lol sorry agian..
x - 3 < -11 or x + 5 >= 14 x < -11+3 or x >= 14-5 x < -8 or x >= 9 So we have an open circle at -8 and we shade to the left then we have a closed circle at 9 and we shade to the right so choice D is the answer
lol it's ok
thanks jim
np
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