Question

find the general solution to 2x(y+1)-yy'=0

Answer 1

its a differential equation

Answer 2

but im stuck in the middle

Answer 3

wait i got it

Answer 4

but if u have \[\int\limits (y(1/(y+1)) \] why do u subtract when u seperate

Answer 5

\[\int\limits y -\int\limits 1/(1+y)\]

Answer 6

why is it subtraction

Answer 7

wait im wrong

Answer 8

?

Answer 9

2x(y+1)=yy'

2x(y+1)/y = y'

2x (1 + 1/y)=y'

2x = y'/(1 + 1/y)

2x dx= dy/(1+1/y)

Answer 10

ok just answer me this

Answer 11

if u want to seperate integrals, do u have to subtract?