a wheel turning with angular speed of 30rad/s is brought to rest with a constant acceleration. it turns 60/rad before it stops. what is its angular acceleration?

Question

anonymous · Answer

try omegaf^2=omegai^2 +2(alpha)(deltatheta)... solve for alpha

anonymous · Answer

-75rad/s^2

anonymous · Answer

You can simply get data from linear functions. Just think of radians and radians/second as a form of distance and speed in metres and metres/second. It's all be conveniently paramaterised to be easily interchangable.

Idest, just replace the word linear, with the word angular.

So: We have v, u and s (initial, final and distance rspctvly) and we want a.

This leaves us with this equation: $$2ar=v ^{2}+u^{2}$$
Now all that's left is to rearrange the formula, and insert the values. 

WHICH I WON'T DO. As I feel it's vital that you learn the properties yourself rather than someone giving you the answer.

anonymous · Answer

thanx!