Question

Solve the equation.

Answer 1

\[\left(\begin{matrix}36 \\ 3x-9\end{matrix}\right)+\left(\begin{matrix}1 \\ x+3\end{matrix}\right)\left(\begin{matrix}13 \\ 3\end{matrix}\right)\]

Answer 2

is this combination?

Answer 3

yes.

Answer 4

This seems simple. Multiply the two last terms

Answer 5

so you will get 13/3x+9

Answer 6

Now the problem we have is that when we add we need the same denomanator and we odn't since one is 3x+9 and one is 3x-9

Answer 7

Si would say that you wld have to multiply the first term by (3x+9) and the second term by (3x-9)

Answer 8

So the denomanator becomes 9x^2-81

Answer 9

or simly we can write it as (3x-9)(3x+9)

Answer 10

Did you get that so far?

Answer 11

yes so far so wait was the answer the first one you posted?

Answer 12

i didnt post the final answer yet

Answer 13

oh sorry i was confused

Answer 14

I am getting an ugly number wait a sec

Answer 15

ok thats fine.

Answer 16

Ok this is what i got it may be the wrong answer

Answer 17

\[(36(3x+9)+13(3x-9))\div(3x-9)(3x+9)\]

Answer 18

then you would distribute and simplify and the answer you recieve is:\[(147x+207)\div \div(9x^2-81)\]

Answer 19

ignore the second division sign that was a mistake

Answer 20

Then you can factor out a 3 on the top and the bottom:
\[3(49x+69)/3(3x^2-27)\]

Answer 21

Then we cross out the threes andwe are left with:
\[(49x+69)/(3x^2+27)\]

Answer 22

I think that i sthe answer

Answer 23

it says the answer is a solution set is that a solution set?

Answer 24

wait a sec

Answer 25

i think it might have to be 2 x's.

Answer 26

Are you sure someone told me that it is the domain and range of the function

Answer 27

Ya it seems to me like the domain and range