a Car passes throough a tollbooth at 8:00 am and begins traveling east at an avarage speed of 45 mph. a second car passes through the same tollbooth at the same time an hour later and travels at an avarage speed of 60 mph. write an equation for each car that relates the number of hours (x) since 8:00 am. to the distance (y) the car has traveled. # please help, im stuck on this one
First car: y=45x Second car: y = 60(x-1)
??
ok so how do i graph this ?
what calculator do you have
just the computers calculator
oh okay... not to sure how to graph that on the computers cal
i just need to draw it out on graphing paper
by hand you would just plug in the 45x into the other equation
then solve for x and then would have your graph equation if I am thinking this out correctly
ok thankyou
I got no medal for giving two equations.
sorry new here, dont really know anout all of this
ca any of you help me with this problem its on my questions [log x ^{3}(5-x ^{2})^{2}\div (x-3)^{4} as the sum/ difference of logarithms with arguments with exponent 1.
I new to this to thanks for the medal
if neither car stopped, at what time will the second car atch up to the first
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