Find the 11th term of the arithmetic sequence. a3 = 20.5 and a8 = 13, a11 = ______.
ok uhmmm first we gata use the formula which i believe is a + (n - 1)d so if a3 = 20.5 then, a3 = a + (n - 1)d n= 3 20.5 = a + (3 - 1)d ----- 1 20.5 = a + 2d ----- 1 then, a8 = a + (n - 1)d n= 8 13 = a + (8 - 1)d -------- 2 13 = a + 7d --------- 2 So we are meant to find what a11 is n = 11, a =? a11 = a + (11-1)d a11 = a - 10d -------3 Well we have a simultaneous eqn already So, 20.5 = a + 2d 13 = a + 7d now lets solve for a in eqn 1 a = 20.5 - 2d -------- 4 substitute in eqn 2 so, 13 = (20.5 - 2d) + 7d 13 = 20.5 + 5d 5d = 13 - 20.5 5d = -7.5 d = -7.5/5 So sub in eqn 1 or 2 to get a so using eqn 2 a = 13 - 7d a = 13 - 7(-7.5/5) a = 23.5 so we have a and d hence a11 = a +(n - 1)d if a = 23.5 , n = 11 then a11 = 23.5 + (11 -1)(-7.5/ 5) a11 = 23.5 + (10)(-1.5)
a 11 = 8.5
a + 2d = 20.5 a + 8d = 13 -6d = 7.5 -d = 1.25 d = -1.25 a - 2.5 = 20.5 a = 20.5 + 2.5 a = 23 a + d = 23 - 1.25 = 21.75 is a2 23 +2(-1.25) = 20.5 is a3 23 + 8(-1.25) = 13 is a8 23 + 11(-1.25) = 9.25 is a11 Please remember to click good answer
your answer is wrong cornzyblack
and your formula is also incorrect
its called openstudy
when did you realise?
mr. lig i tink u gat beef with me u want me to show u a flaw in your work, check line 2, u'll see u did not subtract to get a + 7d = a8, so back off. almost everytym i come here some1 must piss me off
a + 7d = 13 your write i made a typo but atleast i can admit my mistake admit your wrong and your answer is also wrong as well as your method and we have nothing further to talk about lol
am definitely sure am not wrong
lol are you saying im wrong then?
Well, Idk if cornzy is right or not, but lilg, your answer was incorrect. I used yours and got that question wrong.
yes i'm working it out now because of my typo i have to do it again
see lilg if am wrong i would like someone to tell me not u from u, k. Beause you just pointed tha finger at me when u did rubbish
well done cornzyblack you got it right
a11 = 8.5
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