Question

solve :

ln5x+ln(x+1)=0

Answer 1

so far I've done lin5x(x+1)= 0
ln5x^2+5x=0
ln5(x^2+x)=0

Answer 2

and 0= ln1

Answer 3

where do I go from there?

Answer 4

then remove log and you'll have 5x^2+5x-1=0

Answer 5

ln5x+ln(x+1)=0
ln(5x^2+5x) =0
5x^2 +5x=1
solve it through completing square method you will be getting the answer

Answer 6

where does the 1 come from?

Answer 7

0 is equal to ln 1

Answer 8

just factor out the ln and devide both sides by it...u end up with 5x+(x+1)

Answer 9

ln 5x+ln x+1=0
ln(5x*(x+1))=0
taking anti log on both sides
e^0=1
so 5x(x+1)=1
5x^2+5x-1=0
solving using quadratic formula
we get \[x=(-5+\sqrt(5^2-4*5*-1))/10\]
or \[x=(-5+\sqrt(45))/10\]
\[x=(-5+3\sqrt(5))/10\]
and \[x=(-5-3\sqrt(5))/10\]

Answer 10

@Jason Good heavens don't say divide by the log sign.... *restarts heart*

Answer 11

thank you everyone for helping me! @uselessmass people are being nice and helping me out, just like you...you added to the post!

Answer 12

A) He says as he adds another one... :)
and B) that should be
\[(1+x)(5x) = 1, \space \text{not} \space 0\]

Answer 13

still kinda confused but it's getting there!

Answer 14

so I got 5x^2+5x-1 and now i use the quadratic formula right?

Answer 15

yup

Answer 16

okay so I got final answer as [-5-3\sqrt{5}/10\]

Answer 17

\[-5-3\sqrt{5}/10\]