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prove : (p-1)(q-r)+(q-1)(r-p)+(r-1)(p-q) looking for both algebraic and logical explanations
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=0
i mean the above expression equal to 0
prove
are q,p and r in ap?
??
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no
i won't be able to prove it until and unless you give me a relationship between p,q and r
i need a logical explanation
Okay hmm let me try
hey we can
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aravind did you even open it
\[(p-1)(q-r)+(q-1)(r-p)+(r-1)(p-q)\] \[=pq-rp-q+r+qr-pq-r+p+rp-rq-p+q=0.\]
Just cancel out like-terms with different signs.
just open it you will get zero lol
i knw that u needed a logical explanation involving property of cyclic
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