anybody on here know about l'hopital's rule??

Question

slaaibak · Answer

yep

geometry_hater · Answer

you mean this? http://en.wikipedia.org/wiki/L'H%C3%B4pital's_rule Nope i haven't even taken Calc yet

anonymous · Answer

yeah i mean that. and you got any tips or teach me how to use it?

slaaibak · Answer

Read the wikipedia link, they tell you everything you need to know

anonymous · Answer

ok alright thanks

anonymous · Answer

you use it when you have indeterminate form

anonymous · Answer

which is either infinity over infinity or 0/0

anonymous · Answer

could you show me an example of both? please?

anonymous · Answer

say you have the following limit:  $$\lim_{x \rightarrow 4}((x^2 - 16)/(x-4))$$

if you plug 4 in, you would end up with 0/0.  This is an indeterminate form so you need to apply l'hopital's rule which just means you take the derivative of the top and the derivative of the bottom and use it as your new limit equation.  After applying l'hopital's you should have:

$$\lim_{x \rightarrow 4}(2x/1) ----> 2(4) = 8$$

Do the same thing if an equation results in infinity/infinity.  0/0 and infinity/infinity are the two indeterminate forms you need to look out for.  whenever you see them, use l'hopitals.

anonymous · Answer

OHHHHHH!!! I get it now!! Thank you sosososososo  much.