Question

Maclauren series problem,How do I find (f^n)(0)

Answer 1

e^0 = 1

Answer 2

plug in the value of x=0 into the f^n(x)

Answer 3

So say n=3, would this be:
\[f ^{3}e ^{x}\]

Answer 4

f(x) = e^x

f'''(x) = e^x; f'''(0) = e^0 = 1

Answer 5

your just taking successive derivatives and applying your ... whatever its called, to it

Answer 6

Then how are they getting

Answer 7

\[f^{(n)}\] is the nth derivative, so derive your function n times, then fill in 0.

Answer 8

casue e^x would be a typo and is meant to be 5e^x

Answer 9

maybe?

or e^(5x)

Answer 10

I feel stupid...

Answer 11

lol

Answer 12

its ok

Answer 13

Mk, thanks for the help, again

Answer 14

Though 1 quick question, when:
(f^(5))(0) = e^0 = 1
How does that become 5^5?

Answer 15

I believe the original function is \[e^{5x}\]
so when you derive that once you get \[5e^{5x}\]
right?

Answer 16

when you derive it twice you get \[5*5 e^{5x}\]
right?

Answer 17

What do you get when you derive it 5 times?