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OpenStudy (anonymous):
Subtract and give the answer in simplest form:
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OpenStudy (anonymous):
\[3x \over x-5\] - \[5 \over 5-x\]
OpenStudy (anonymous):
Answer choices:
A. 3
B. \[3x-5 \over x-5\]
C. \[3x+5 \over x-5 \]
OpenStudy (anonymous):
3x(5-x)- 5(x-5) (3x+5)(5-x)
= -------------- = ----------
(x-5)(5-x) (x-5)(5-x)
= 3x+5
----
x - 5
OpenStudy (anonymous):
How did you group (5-x) and (x-5)???
OpenStudy (anonymous):
(5-x)(x-5) is the multiple of 5-x and x-5
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OpenStudy (anonymous):
you multiply both original fractions by (5-x)(x-5)
OpenStudy (anonymous):
I know, but you can't group it because it's different
we can group (5-x) and (5-x), not (5-x)(x-5)
your answer is wrong
OpenStudy (anonymous):
ok - -i'll check it out with pen and paper
OpenStudy (anonymous):
its correct
OpenStudy (anonymous):
oh, I'm stupid
\[3x(5-x)-5(x-5)=3x(5-x)-5(-1)(5-x)=3x(5-x)+5(5-x)=(5-x)(3x+5)\]
yes, it's correct)
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OpenStudy (anonymous):
lol - human error - i was like this a few days ago - only worse
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