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OpenStudy (anonymous):
OpenStudy (anonymous):
PLZ HELP!!!
OpenStudy (anonymous):
X intercepts are where the equation is equal to 0.
OpenStudy (anonymous):
Ok. So what is the answer?
OpenStudy (anonymous):
do you just want the answer or do you want to learn the material?
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OpenStudy (anonymous):
Just the answer would be nice!
OpenStudy (anonymous):
that's not how I roll, sorry
OpenStudy (anonymous):
ok then can u help me learn how to solve it?
OpenStudy (anonymous):
ok, f(x) = x+2, or any function, is like saying y = x+2. in other words, in this context, f(x) is the same thing as y. And to find the x-intercept, i.e. the place where the graph hits the x axis, that's where Y = 0. Or, where f(x) is equal to 0. So step 1 is to replace f(x) with 0. What do you get?
OpenStudy (anonymous):
?
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OpenStudy (anonymous):
i don't understand
OpenStudy (anonymous):
What's the equation you're starting with?
OpenStudy (anonymous):
4x^2=12
OpenStudy (anonymous):
well in part 2 they converted it to a function f(x) in terms of x
OpenStudy (anonymous):
ok?
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OpenStudy (anonymous):
what is that equation?
OpenStudy (anonymous):
idk
OpenStudy (anonymous):
it's written in your attachment
OpenStudy (anonymous):
How did you do part 1?
OpenStudy (anonymous):
i put 4x^2=12 in to mathway.com
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