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Mathematics 8 Online
OpenStudy (anonymous):

See attachment.

OpenStudy (anonymous):

OpenStudy (anonymous):

PLZ HELP!!!

OpenStudy (anonymous):

X intercepts are where the equation is equal to 0.

OpenStudy (anonymous):

Ok. So what is the answer?

OpenStudy (anonymous):

do you just want the answer or do you want to learn the material?

OpenStudy (anonymous):

Just the answer would be nice!

OpenStudy (anonymous):

that's not how I roll, sorry

OpenStudy (anonymous):

ok then can u help me learn how to solve it?

OpenStudy (anonymous):

ok, f(x) = x+2, or any function, is like saying y = x+2. in other words, in this context, f(x) is the same thing as y. And to find the x-intercept, i.e. the place where the graph hits the x axis, that's where Y = 0. Or, where f(x) is equal to 0. So step 1 is to replace f(x) with 0. What do you get?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

i don't understand

OpenStudy (anonymous):

What's the equation you're starting with?

OpenStudy (anonymous):

4x^2=12

OpenStudy (anonymous):

well in part 2 they converted it to a function f(x) in terms of x

OpenStudy (anonymous):

ok?

OpenStudy (anonymous):

what is that equation?

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

it's written in your attachment

OpenStudy (anonymous):

How did you do part 1?

OpenStudy (anonymous):

i put 4x^2=12 in to mathway.com

OpenStudy (anonymous):

well ust do that again for part 2

OpenStudy (anonymous):

ok ill try that. One sec

OpenStudy (anonymous):

i got \[\sqrt{3} , -\sqrt{3}\]

OpenStudy (anonymous):

great that's your answer

OpenStudy (anonymous):

YAY!!!! THX ^_^

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