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Help me resolve this equation? h (t) = -0.6(t-1.5)^2 + 1.35 We are looking for the value of t. h = 1
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are you trying to solve \[-0.6(t-1.5)^2 + 1.35 =1\]?
No, I am trying to find the value of t.
subtract 1.35 from both sides to get \[h (t) = -0.6(t-1.5)^2 =-.35 \]
yes i see, we are looking for t.
then divide by -.06 to get \[(t-1.5)^2=\frac{7}{12}\]
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so \[t-1.5=\pm\sqrt{\frac{7}{12}}\]
and finally \[t=1.5\pm\sqrt{\frac{7}{12}}\]
Thank you! That helped a lot
yw
I have one more question. When you found 1.35, and put it on the other side to get -.35, where did the 1 go? Thanks again
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