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Mathematics 8 Online
OpenStudy (anonymous):

five student are lined up in a cafeteria( alex,bryan,christy,dawson,and eric)

OpenStudy (anonymous):

how many different ways can they line up if bryan and eric must be at either end?

OpenStudy (ragingsquirrel):

ok... the rest? Also, my name is Alex. XD

OpenStudy (ragingsquirrel):

lemme write that out. Gimme a second.

OpenStudy (ragingsquirrel):

my best guess is 6.

OpenStudy (mathmate):

So really there are only three persons to line up, multiplied by two ways, either Alex or Eric at the head of the queue.

OpenStudy (mathmate):

Don't forget either Alex or Eric could be up front.

OpenStudy (ragingsquirrel):

I still come up to 6...

OpenStudy (anonymous):

so would it be like this |dw:1323922212001:dw|

OpenStudy (anonymous):

|dw:1323922255733:dw|

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