the lengths of the sides of a triangle are x, 3 and 5 what is the possible vaule of x?
4
why
triples. :l
4 if it is a right angled triangle
yea abhed is right....theres a theorem where it says somthing about the addition or subtraction of the sides or somthing has to be equal to a certain quantity
x^2+3^2=5^2 x^2=25-9 x^2=16 x=4
ok so if a triangles sisdes are x, 33, and 41 how would i solve this one?
pythagorean theorem. Should've remembered that. is x the hypotneuse? or however you spell that.
no because the triangle is not drawn
x can be taken as the hypotenuse only if it is th largest side
If it's unspecified, how would you solve that?
add 33+41?
Assuming X is the hypotenuse, you would do: \[33^{2}+41^{2}=X ^{2}\]
So X would be the square root of 2770, or 52.63078... There's probably a much simpler way to do that. But regardless, the answer is the same.
there is.....all you need to do is add the two shortest side and they have to be greater than the largest side
That's true, but how would it get you the answer? That would just mean X<74. Doesn't help much.
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