the diagonal of a rectangle measure 61cm.the width of the rectangle is 11cm find the length of the rectangle.
please help
is there anyone to help me
The diagonal cuts the rectangle into two right-triangles, with the hypotenuse = 61 and one of the (shorter) sides 11. Use Pythagoras theorem for the length L, where L^2+11^2=61^2 Solve for L.
thank you for your help
here another question can someone help me please. here the question find the length of side a in the right triangle if b=6 and c=10 can someone help
Would c=10 be a hypotenuse?
ok thank
i need to know what would a be
If c=10 is a hypotenuse, then a=8 (sqrt(10^2-6^2). If it is not, then we need to find the hypotenuse by sqrt(6^2+10^2)=4sqrt(10)
i have 8 i was just making sure i was correct thank you
You're welcome!
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