Question

Write the equation of the line that passes through (3, 6) and (0, –3) in slope-intercept form.

Answer 1

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Answer 2

Find the slope first... (6-(-3))/(3-0) which is 3. Then use point slope form: y-y1=m(x-x1) and plug in 3 for m (slope) and use either point for x1,y1. Like this:
y-6=3(x-3).

Then simplify to get slope intercept form:
y-6=3x-9
y=3x-3.

Answer 3

all right check the way..
(3,6) and (0,3)
from slope = Y2- Y1/X2 -x1
where by -3 -6/0 - 3
-9/-3 = 3
slope is 3
from slope =Y - Y1/X - X1
3 =y -6/x-3
y-6 =3(x-3)
y-6=3x-9
y-6 = 3x -(9+6)
y=3x -3
The equation is y = 3x - 3
Got it am Joel