Question

3+logbase2(2x-5)=log(5x-7)

Answer 1

pleae post with equation editor

Answer 2

fr log 5x-7 what is the base?is base given?

Answer 3

this log(5x-7)...are you sure it doesn't have a base 2? Because this problem seems hard the way it appears...

Answer 4

\[\log_28+\log_2(2x-5) = \log_2(5x-7)\]

Answer 5

is the answer x=3?

Answer 6

the same questions as lgbsallote

Answer 7

nutty is it x=3?

Answer 8

for log (5x-7) the base is 2

Answer 9

then answer is x=3?u want solution?

Answer 10

I dont' think so

Answer 11

substitute and see it is rite victorarana.....!!!!!!!!!!!!!!!

Answer 12

then the solution is to put all the logs on one side. it becomes logbase 2 (2x-5)/(5x-7) = -3. 2^-3 = 2x - 5/5x - 7. 1/8 = (2x-5)/(5x-7). cross multiply. 5x - 7 = 16x - 40. 11x = 33. x = 3. King is right

Answer 13

thnx igbasallote!!!!!!

Answer 14

let me think

Answer 15

can i hve the solution plzzz

Answer 16

yes it's not correct

Answer 17

\[3 = \log_2\frac{5x-7}{2x-5}\]

Answer 18

so \[2^3 = \frac{5x-7}{2x-5}\]

Answer 19

ya

Answer 20

solving for x \[x=\frac{33}{14}\]

Answer 21

are you agree? King?

Answer 22

no u hav solved wrong

Answer 23

mm you're right it was 33/11 = 3

Answer 24

ya gud!

Answer 25

sooo wats da answer knw cauze am soo confused

Answer 26

answer is x=3

Answer 27

ok?

Answer 28

oky