Question

A giant pulls with a force of 335 N on a rope at an angle of θ = 20 degrees to steal a 46 kg brownie.
As a result, the brownie slides at a constant velocity.

(d) What is the horizontal component of the rope tension?
(e) What is the strength (magnitude) of the frictional force between the brownie and the floor?
(f) What is the vertical component of the rope tension?
(g) What is the strength (magnitude) of the support force of the floor against the brownie?
(h) What is the coefficient of kinetic friction between the brownie and the floor?

Answer 1

you might want to put this in the Physics group.

Answer 2

d) horizontal component: i component of vector form. 335cos(20)
e) constant velocity=no acceleration=335N
f) j component of vector form. 335sin(20)
g) it's asking for normal force. N=mg
h) F(pull)-F(friction)=0. set to equal 0 since it's constant velocity=no aceleration

Answer 3

elica the answer to e is -335cos 20 because it is equal to horizontal component thats y i wont accelerate