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Water is being poured into a conical reservoir at the rate of pi cubic feet per second. The reservoir has a radius of 6 feet across the top and a height of 12 feet. At what rate is the depth of the water increasing when the depth is 6 feet?
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V = 1/3 pi r^2h You have been given dV/dt So use implicit differentiation, substitute and solve for dh/dt
thanks for that still trying to solve problem though XD
What's XD?
I got 1/2 ft/sec
can u explain?
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ugh im never going to get this =(
i got 9 pi
|dw:1324431291655:dw|
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