How do I figure this problem... The perimeter of a rectangular sign is not to exceed 50 ft. The length is to be twice the width. What widths will meet these conditions?

Question

anonymous · Answer

If the width is W, and the length is L, what expression represents the perimeter of the sign?

anonymous · Answer

Try to work out first the maximum so forget that it is a 'less than' problrm. You need two equations. Can you think of any equations you can make with these instructions?

anonymous · Answer

25+25 im lost

anonymous · Answer

If the length is L, for example, twice the length is "2L".

anonymous · Answer

So in terms of L and W, how would you find the perimeter of a sign?

anonymous · Answer

2l +4w

anonymous · Answer

2L

anonymous · Answer

You're close.  Forget the "length is twice the width" part for just a second, and pretend you just know the length is L and the width is W.

mertsj · Answer

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