write the equation of the line passing through (-3,2) and is parallel to and perpendicular to the line y=6x-3
is it parallel or perpendicular
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both write one for being perpendicular and one of being parallel
PLEASE AND THANKYOU :)
for perpendicular: the slope of the line is -1/6 y = -(1/6)x +c 2 = -1/6(-3) +c c= 3/2 =>line: y=-(1/6)x+3/2
for parallel: the slope of the line is 6 =>y=6x+c =>2=-18+c =>c=20 =>line: y=6x+20
It's incorrect how did you calculated the c in perpendicular line.
thats what i was giong to ask
when it's perpendicular the equation must be y = -1/6x - 8/3
i dont know where c even came from haha and could you explain how you got the answer and okay thankyou
where did the eight and three come from ugh!!
if the line is perpendicular the slope will be - 1/6, and so substitute the value of slope and point in point slope equation, manipulate it and get it in slope intercept.
thats what i need help with thats what i dont know how to do haha
k wait i will draw it.
okay thanks
I am extremly sorry the equation of perpendicular line will be y = -1/6x - 3/2
dont worry about it that was great help i know who to go to if i need help!! :) :)
for parallel line : y - 6x + 20
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