Question

PLEASE SOMEONE HELP ME.

if you were to use substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 2x+5y-2z=-1 x+3y+z=-2 3x-2y+3x=-17

A. -y-4x=3
-11y=-11
B.11y=3
7y+6x=-11
C.4x+11y=-5
-11=-11
D.-y=-5
6x+7y=-11

Answer 1

so x from second equation will be

x=-2-3y-z

2x+5y-2z=-1
3x-2y+3z=-17 hope that this is hence right,correct with 3z not with 3x before =

so when x=-2-3y-z will get

2(-2-3y-z)+5y-2z=-1
3(-2-3y-z)-2y+3z=-17

-4-6y-2z+5y-2z=-1
-6-9y-3z-2y+3z=-17

-y-4z=3
-11y=-11 so from this result that y=1 so than

-1-4z=3 so -4z=4 so z=4/(-4)=-1 so z=-1 so than

x=-2-3(1)-(-1)=-2-3+1=-5+1=-4 so x=-4

x=-4
y=1
z=-1

Answer 2

just choose the correct answer choice A,B,C OR D

Answer 3

A but there need to be -4z

Answer 4

so if you izolated x

Answer 5

robtobey how do you say ?

Answer 6

i think i typed it wrong.. let me see !

Answer 7

2x-5y-2z=-1
x+3y+z=-2
3x-2y+3x=-17

Answer 8

Correction 3x-2y+3z=17

Answer 9

equale -17

Answer 10

yes, my bad

Answer 11

A Mathematica solution with comments is attached.

Answer 12

Thank you for the medal.

Answer 13

Any time... Im not a hater..

Answer 14

and medal for my work ???

Answer 15

thank yo

Answer 16

thank you and good luck