Question

Cl2 + NaBr -> New Salt + Non-metal

Answer 1

This is a single displacement reaction.

Answer 2

I put NaCl2 + Br is it correct?

Answer 3

Using the valencies you can see that it is correct because Br is left with 0 valency , a non-metal...so it is correct

Answer 4

okay. thank you

Answer 5

Sorry but i disagree, slightly your salt is going to be NaCl and you should have to of them. Inorder to not ruin the conservation of matter deal. So your products would be 2NaCl and 2Br

Answer 6

ohhh, I need to balance the equation.

Answer 7

I told only the way it is correct ..
If you want it balanced then zbay is correct..

Answer 8

How about when it is Metal + Acid -> Salt + H2 (g)

For ex. Fe (III) + H2SO4 -> Fe3SO4 + H2 (g)?

Answer 9

yea that looks right just remember to check the charge of your ion and insure that they match up with the other, this will give you your molecule or formula unit

Answer 10

That's the problem I don't know the charge of my ion: SO4, but I believe it's -1

Answer 11

Balance it using the given way...
1) redox balance.
2) charge balance. (you use H for acidic environments as in your case , and OH for basic environments)
3) Mass balance.

Answer 12

never mind it is SO4-2. So is it going to be Fe-2(SO4)3?

Answer 13

no it is -2 on SO4

Answer 14

So it's Fe2(SO4)3?

Answer 15

Yes

Answer 16

As I told you above if you go in the series of balancing(shown above).. you wont get confused

Answer 17

what do you mean by redox balance?

Answer 18

What if I have like an element like Fr2O + H20 -> Base. Is it going to be Fr2(OH) since OH is -1 and Fr +1?

Answer 19

Redox balance means oxidation reduction balance..there are several definitions of oxidation & reduction.

Answer 20

... I don't understand.

Answer 21

No no no you are getting confused,

Answer 22

yes I am.

Answer 23

What if I have like an element like Fr2O + H20 -> Base. Is it going to be Fr2(OH) since OH is -1 and Fr +1? ...... THIS ONE IS CORRECT but I just wanted to clear that the simple balancing method is not valid for all type of equations that's why I put forward the best balancing method i.e redox balancing

Answer 24

ohhh... can you give me an example of how you would do a redox balancing?

Answer 25

I have material for you but it is in Italian therefore I may share some links..
1) http://chemistry.about.com/od/generalchemistry/ss/redoxbal.htm
2) http://www.youtube.com/watch?v=yp60-oVxrT4

Answer 26

thank you!

Answer 27

There's still a problem with the answers to the original post. When you have one halogen replacing another, \[Cl{_2} + NaBr \rightarrow \]since both chlorine and bromine are in the same family, they will have the same charge (-1). It is a single displacement, but milliex, you are allowing the formula of the reactants to determine the formula of the products. You have to look at the CHARGES of the pieces that will be combined. When chlorine replaces bromine, both will combine with sodium in the same ratio\[\rightarrow NaCl + Br{_2}\] Chlorine and bromine both have to be diatomic, for reasons you'll probably get to when you talk about bonding. Now put the whole reaction together.\[Cl{_2} + NaBr \rightarrow NaCl + Br{_2}\] Now balance.\[Cl{_2} + 2NaBr \rightarrow 2NaCl + Br{_2}\]